28=40t-16t^2

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Solution for 28=40t-16t^2 equation:



28=40t-16t^2
We move all terms to the left:
28-(40t-16t^2)=0
We get rid of parentheses
16t^2-40t+28=0
a = 16; b = -40; c = +28;
Δ = b2-4ac
Δ = -402-4·16·28
Δ = -192
Delta is less than zero, so there is no solution for the equation

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